Question 61
If a man completes $$\frac{3}{7}$$ work in 6 days, then how many more days will he require for completing the remaining work?
Solution
Given,
A man complete $$\frac{3}{7\ }$$ unit of work in 6 days.
So, $$\frac{1}{7\ }=2\ days$$
$$1\ unit=2\times\ 7\ days$$
= 14 days
So, A man requires 14 days to finish the complete work.
Number of days required to complete the remaining work :
= 14 - 6 = 8 days.
hence, Option A is correct.
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