Question 61

If a man completes $$\frac{3}{7}$$ work in 6 days, then how many more days will he require for completing the remaining work?

Solution

Given,

A man complete $$\frac{3}{7\ }$$ unit of work in 6 days.

So, $$\frac{1}{7\ }=2\ days$$

$$1\ unit=2\times\ 7\ days$$

= 14 days

So, A man requires 14 days to finish the complete work.

Number of days required to complete the remaining work :

= 14 - 6 = 8 days.

hence, Option A is correct.

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