Given that,
$$ \dfrac{a}{b} =\dfrac{2}{3}=k$$
So, a=2k and b=3k
Now substituting the values,
$$\Rightarrow \dfrac{(5a - 2b)}{(5a+ 2b)}=\dfrac{5\times 2k -2\times 3k}{5\times 2k +2\times 3k}$$
$$\Rightarrow \dfrac{5\times 2k -2\times 3k}{5\times 2k +2\times 3k}=\dfrac{4k}{16k}=\dfrac{1}{4}$$
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