Question 6
The sum of the squares to two natural consecutive odd numbers is 394. The sum
of the numbers is
Solution
Let first no. Be x
2nd no.will be x+2
x²+(x+2)²=394
x²+x²+4x+4=394
2x²+4x=390
2(x²+2x)=390
x²+2x=195
x(x+2)=195
x+2=195/x
x=195/x-2
So no is 13 and 15
so the sum will be = 13+15 = 28
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