ABCD is a parallelogram in which diagonals AC and BD intersect at O. AE and DF are perpendiculars on BC at E and F, respectively. Which of the following is NOT true?

It is given that  ABCD is a parallelogram, in which AC and BD are the diagonals of a parallelogram, which intersects at O.

AE and DF are perpendicular to E and F on BC.

Now in $$\triangle$$ ADC and $$\triangle$$ABD

$$\angle$$AEB=$$\angle$$DFC    ---------(perpendicular always makes $$90^\circ$$)

AE = DF  -----------(two perpendiculars one-two parallel lines always have the same length)

AB=DC  -----------(opposite side of the parallelogram have the same length)

Hence $$\triangle AEB \cong \triangle DEC $$ (Side Side Angle)