A trader had 12 quintals of wheat. He sold a part of it at 13% profit and the rest at 23% profit, so that he made a total profit of 17 %. How much wheat did he sell at 23% profit?
1 quintal = 100 kg => 12 quintals = 1200 kg
Let the part he sold at 23% profit = $$x$$ kg
=> Part he sold at 13% profit = $$(1200 - x)$$ kg
Total profit made by the trader = 17%
=> $$23x + 13 (1200 - x) = 17 \times 1200$$
=> $$23x + (13 \times 1200) - 13x = 17 \times 1200$$
=> $$10x = 1200 \times (17 - 13)$$
=> $$x = 120 \times 4 = 480$$ kg
=> Ans - (C)
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