A student multiplied a number by 6/13 instead of 13/6. What is the percentage error in the calculation?
Let the number be 78
When the student multiplied it by 6/13, => original result = $$\frac{6}{13} \times 78 = 36$$
When the student multiply it by 13/6, => New result = $$\frac{13}{6} \times 78 = 169$$
=> Percentage error in calculation = $$\frac{(169 - 36)}{169} \times 100$$
= $$\frac{13300}{169} = 78.69 \approx 78.7\%$$
=> Ans - (D)
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