Solution
= $$3\div3\ of\ 3+2\div4+(4\times2-2)\div12+4$$
= $$\frac{3}{9}+\frac{2}{4}+(8-2)\div12+4$$
= $$\frac{1}{3}+\frac{1}{2}+\frac{6}{12}+4$$
= $$\frac{1}{3}+\frac{1}{2}+\frac{1}{2}+4$$
= $$\frac{1}{3}+1+4$$
= $$5\frac{1}{3}$$
= $$\frac{16}{3}$$
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