Question 58

What is the value of $$3 \div 3 of 3 + 2 \div 4 + (4 \times 2 - 2) \div 12 + 4$$?

= $$3\div3\ of\ 3+2\div4+(4\times2-2)\div12+4$$

= $$\frac{3}{9}+\frac{2}{4}+(8-2)\div12+4$$

= $$\frac{1}{3}+\frac{1}{2}+\frac{6}{12}+4$$

= $$\frac{1}{3}+\frac{1}{2}+\frac{1}{2}+4$$

= $$\frac{1}{3}+1+4$$

= $$5\frac{1}{3}$$

= $$\frac{16}{3}$$

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