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Question 58
What is the value of $$3 \div 3 of 3 + 2 \div 4 + (4 \times 2 - 2) \div 12 + 4$$?
Solution
=Â $$3\div3\ of\ 3+2\div4+(4\times2-2)\div12+4$$
=Â $$\frac{3}{9}+\frac{2}{4}+(8-2)\div12+4$$
= $$\frac{1}{3}+\frac{1}{2}+\frac{6}{12}+4$$
=Â $$\frac{1}{3}+\frac{1}{2}+\frac{1}{2}+4$$Â
=Â $$\frac{1}{3}+1+4$$
=Â $$5\frac{1}{3}$$
=Â $$\frac{16}{3}$$
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