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The area of a field in the shape of a regular hexagon is $$2400 \sqrt{3} m^2$$. The cost of fencing the field at ₹16.80/metre is:
Area of a hexagon = $$\frac{3\sqrt{3}a^2}{2}$$
a = side
$$2400 \sqrt{3} = \frac{3\sqrt{3}a^2}{2}$$
$$a^2 = 1600$$
a = 40 m
Perimeter = 6a = 6 $$\times$$40 = 240 m
The cost of fencing the field = 240 $$\times$$ 16.8 = Rs.4032
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