Places A and B are 144 km apart. Two cars start simultaneously, one from A and the other from B. If they move in the same direction, they meet after 12 hours, but if they move towards each other they meet after $$\frac{9}{8}$$ hours. The speed (in km/h)of the car moving at a faster speed, is:

Speed of faster car = v1

Speed of slower car = v2

Case I: Cars travel in same direction

144 km distance covered in 12 hours so,

Relative speed = v1 - v2

v1 - v2 = 144/12 = 12 ---(1)

Case II: Cars in opposite direction

144 km distance covered in $$\frac{9}{8}$$ hours so,

Relative speed = v1 + v2
v1 + v2 = $$\frac{144}{\frac{9}{8}}$$ = 128 ---(2),

From eq(1) and (2),

2v1 = 12 + 128

v1 = 140/2 = 70 km/hr

$$\therefore$ The speed of faster car is 70 km/hr.