Solution
Given,
$$\frac{x}{y}=\frac{5}{7}$$
Putting these value in equation given in the question.
$$\therefore\ \frac{6x-y}{5x+3y}=\frac{\left(6\times5\right)-7}{\left(5\times5\right)+\left(3\times7\right)}$$
= $$\frac{23}{46}=\frac{1}{2}$$
= 1 : 2
Hence, Option D is correct.
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