Question 58

Find the value of p, when p = (5 $$\div$$ 6) of 54 - 40 $$\div$$ 10 - 41 - 22.

Solution

p = (5 $$\div$$ 6) of 54 - 40 $$\div$$ 10 - 41 - 22

p = $$\frac{5}{6}\times54-\frac{40}{10}-41-22$$

p = $$5\times9-4-41-22$$

p = $$45-67$$

p = -22

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