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Question 57

There are two numbers such that the first number is four times of the second number. If their average is 65, then what is the second number?

Let's assume the first and second numbers are 'y' and 'z' respectively.

There are two numbers such that the first number is four times of the second number.

y = 4z    Eq.(i)

If their average is 65.

$$\frac{y+z}{2}\ =\ 65$$

y+z = 130    Eq.(ii)

Put Eq.(i) in Eq.(ii).

4z+z = 130

5z = 130

z = 26

The second number = 26

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