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C and D together can make a chair in 4 days and C alone can make this chair in 12 days. In how many days D alone can make this chair?
C+D = 4 days
C = 12 days
Total work = lcm(4,12)
=12
Efficiency of C+D= $$12\div4$$ =3
Efficiency of C = $$12\div12$$ =1
So ,
Efficiency of D= (Efficiency of C+D)-(Efficiency of C )
= 2
So, D can work alone = $$total work\div2$$
= 6 days
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