A takes 10 minutes more than B in covering a certain distance. If their speeds are in the ratio of 3 : 4, then what is the time taken by B to cover the same distance?
Given ,Â
Distance by A,B= DÂ
Speed ratio= 3:4
Time= $$\frac{distance}{speed}$$
Time taken by A - Time taken by B = 10min
$$\frac{D}{3y}$$-$$\frac{D}{4y}$$=10
$$\frac{D}{12y}$$ =10
D= 120y m
Time taken by B=Â $$\frac{120y}{4y}$$
              = 30 min
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