A bag contains one rupee, 50 paise and 25 paise coins in the proportion 5 : 7 : 9. If the total amount in the bag is ₹430, then how many 25 paise coins are there?
A bag contains one rupee, 50 paise and 25 paise coins in the proportion 5 : 7 : 9.
Here money is indifferent value. So we need to convert them into a single base.
Ratio ==> $$5\times4 : 7\times2 : 9\times1$$ [one rupee = $$4\times $$ 25 paise] [50 paise= $$2\times $$ 25 paise] [25 paise = $$1\times $$ 25 paise]
==> 20 : 14 : 9
If the total amount in the bag is ₹430.
20y+14y+9y = 43000 [₹430 will be converted into paise.]
43y = 43000
y = 1000
Amount in the form of 25 paise coins = 9y = 9000 paise = ₹90
Number of 25 paise coins = $$90\times4$$ = 360
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