Question 59

The train crosses two platforms of lengths 1000 m and 600 m in 80 seconds and 60 seconds respectively. What is the length of the train?

Solution

The train crosses two platforms of lengths 1000 m and 600 m in 80 seconds and 60 seconds respectively.

Let's assume the length of the train is 'y'.

$$\frac{\left(y+1000\right)}{80}=\frac{\left(y+600\right)}{60}$$

$$\frac{\left(y+1000\right)}{4}=\frac{\left(y+600\right)}{3}$$

3y+3000 = 4y+2400

4y - 3y = 3000-2400 = 600

length of the train = y = 600 m

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