In an examination, Anita scored 31% marks and failed by 16 marks. Sunita scored 40% marks and obtained 56 marks more than those required to pass. Find the minimum marks required to pass.
Anita scored 31% marks and failed by 16 marks and Sunita scored 40% marks and obtained 56 marks more than those required to pass.
Difference of percentage = difference of marks
40% - 31% = 16 + 56 (Anita is failed and Sunita is passed so marks will be added)
9% = 72 marks
56 marks = $$\frac{9}{72} \times 56 = 7%$$
Sunita scored 40% marks and obtained 56 marks more than those required to pass so,
Minimum passing marks = 40% - 7% = 33%
7% = 56 marks
33% =Â $$\frac{56}{7} \times 33 = 264$$
Create a FREE account and get: