$$\left(\frac{2\tan30^{\circ}}{1-\tan^230^{\circ}}\right)=\frac{2\left(\frac{1}{\sqrt{3}}\right)}{1-\left(\frac{1}{\sqrt{3}}\right)^2}$$
$$=\frac{2\left(\frac{1}{\sqrt{3}}\right)}{1-\frac{1}{3}}$$
$$=\frac{\frac{2}{\sqrt{3}}}{\frac{2}{3}}$$
$$=\frac{3}{\sqrt{3}}$$
$$=\sqrt{3}$$
Hence, the correct answer is Option A
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