Amal buys 110 kg of syrup and 120 kg of juice, syrup being 20% less costly than juice, per kg. He sells 10 kg of syrup at 10% profit and 20 kg of juice at 20% profit. Mixing the remaining juice and syrup, Amal sells the mixture at ₹ 308.32 per kg and makes an overall profit of 64%. Then, Amal’s cost price for syrup, in rupees per kg, is
Correct Answer: 160
Total syrup - 110 kg
Total juice - 120 kg
It is given, cost price of syrup is 20% less than the cost price of juice.
Let the cost price of juice per kg be 10CP
Cost price of syrup per kg is 8CP
10kg syrup -> cost price = 80CP
It is given, 10kg syrup is sold at 10% profit. This implies selling price = 1.1*80CP = 88CP
20kg juice -> cost price = 200CP
It is given, 20kg juice is sold at 20% profit. This implies selling price = 1.2*200CP = 240CP
It is given, Mixing the remaining juice and syrup, Amal sells the mixture at ₹ 308.32 per kg
Selling price of the remaining mixture = 308.32*200 = Rs 61664
Total S.P = 61664 + 328CP
Total C.P = 880CP + 1200CP = 2080CP
Overall profit = 64%
$$61664+328CP=\frac{164}{100}\left(2080CP\right)$$
Solving, we get CP = 20
Cost price for syrup per kg = 8CP = 8*20 = Rs 160
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