Rani bought more apples than oranges. She sells apples at Rs. 23 apiece and makes 15% profit. She sells oranges at Rs. 10 a piece and makes 25% profit. If she gets Rs. 653 after selling all the apples and oranges, find her profit percentage.

Let number of apples = $$x$$ and oranges = $$y$$

=> $$23x + 10y = 653$$   $$(x > y)$$

Since, 653 has last digit 3, which is possible when 23 is multiplies by 1,11,21,31 and so on.

Also, $$x > y$$ => $$x = 21$$ and $$y = 17$$

=> C.P. of 1 apple = $$\frac{100}{115} \times 23 = 20$$

C.P. of 1 orange = $$\frac{100}{125} \times 10 = 8$$

=> Total C.P. = $$(21 \times 20) + (17 \times 8) = 420 + 136 = 556$$

$$\therefore$$ Profit % = $$\frac{653 - 556}{556} \times 100 = 17.4 \%$$