Question 55

A dealer sold an article at 6% loss. Had he sold it for Rs. 64 more, he would have made a profit of 10%. Then the cost of the article is

Solution

Let the cost price of the article = Rs. $$100x$$

Loss % = 6%

=> Selling price = $$100x \times \frac{94}{100}=Rs.$$ $$94x$$

If SP is Rs. 64 more, => New SP = Rs. $$(94x+64)$$

=> Profit % = $$\frac{(94x+64)-100x}{100x} \times 100=10$$

=> $$64-6x=10x$$

=> $$10x+6x=16x=64$$

=> $$x=\frac{64}{16}=4$$

$$\therefore$$ Cost Price = $$100 \times 4=Rs.$$ $$400$$

=> Ans - (A)

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