What is the value of $$(3 \times 4  of  12 \div 2) \div 9 \times 4 + 4 \div 8 + 3 \times 2 ?$$

using the BODMAS rule { priority brackets > of > division > multiplication > addition > subtraction}

solving the bracket first (1st priority brackets)

$$(3 \times 4  of  12 \div 2)$$ , now since 'of' is the priority hence it should be solved first

simplifying  it we get

 $$(3 \times 4\times12 \div 2)$$ (here 4 of 12 is $$4\times12$$ ) =$$(3 \times 4\times 6)$$

substituting in original  question we get

$$(3 \times 4\times 6) \div 9 \times 4 + 4 \div 8 + 3 \times 2 $$

simpliying it further we get

$$\frac{(3 \times 4\times 6)}{9} \times 4 +\frac{4}{8}+ 3 \times 2 $$

= 32+$$\frac{1}{2}$$+ 6 = $$\frac{77}{2}$$