Sign in
Please select an account to continue using cracku.in
↓ →
The data given below shows the marks obtained by various students.
What is the mean marks (Correct up to two decimal places) of given data?
To find the mean of the class interval , mid point of class interval of marks is obtained as shown in the table
Then product of marks and no of students is obtained
Total number of students = 30
$$\sum$$(marks $$\times no of students $$) = 66+104+75+119+76 = 440
mean = $$\frac{\sum(marks \times no. students)}{total students}$$ = $$\frac{440}{30}$$
= 14.67
Was this solution helpful?
Create a FREE account and get:
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
