If A, B and c can respectively complete a piece of work in 20, 24 and 36 days respectively, how many days will they take to complete the work, if they work together ?
A=20 days, B = 24 days and C = 36 days
Total work = L.C.M of 20, 24, 36 = 360 units
A's 1 day work =Â $$\frac{360}{20}=18 Â units$$
B's 1 day work = $$\frac{360}{24}=15Â units$$
C's 1 day work = $$\frac{360}{36}=Â 10 units$$
A+B+C will take to complete the work =Â $$\frac{360}{43}=8\frac{16}{43}$$
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