Question 53

If $$a : b : c = 1 : 3 : 5$$, what is the value of $$\frac{4a - b + 2c}{3(a + b + c)}$$ ?

Solution

Let a = x; b= 3x, c=5x

$$\frac{4a - b + 2c}{3(a + b + c)}=\frac{\left(4x-3x+10x\right)}{3\left(x+3x+5x\right)}=\frac{11}{27}$$


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