A shopkeeper sold two items. The selling price of the first item equals the cost price of the second item. He sold the first item at a profit of 20% and the second item at a loss of 10%. What is his overall profit’ loss percent?
Let the cost price of first item = 100C
Profit on first item = 20%
Selling price of first item = $$\frac{120}{100}\times$$100C = 120C
The selling price of the first item equals the cost price of the second item.
Cost price of the second item = 120C
Loss on second item = 10%
Selling price of second item = $$\frac{90}{100}\times$$120C = 108C
Total cost price = 100C + 120C = 220C
Total selling price = 120C + 108C = 228C
Overall profit percentage = $$\frac{228C-220C}{220C}\times100$$
= $$\frac{8C}{220C}\times100$$
= $$\frac{40}{11}$$
= $$3\frac{7}{11}\%$$
Hence, the correct answer is Option A
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