In triangle ABC, D and E are two points on the sides AB and AC respectively so that DE $$\parallel$$ BC and $$\frac{AD}{BD} = \frac{3}{4}$$. The ratio of the area of trapezium DECB to the area of $$\triangle$$ABC is:

A

40 : 49

B

49 : 40

C

49 : 33

D

33 : 49