Question 52

A dealer buys an article marked at ₹30000 with two successive discounts of 20% and 5%. He spends ₹1200 on repairs and sells it for ₹30000, what is his profit/loss percent?

Solution

Given,

Marked price of the article = ₹30000

Price of the article after 20% discount = $$=\frac{80}{100}\times30000=24000$$

Price of the article after 5% successive discount = $$=\frac{95}{100}\times24000=22800$$

Cost on repairs = ₹1200

$$\therefore\ $$Cost Price of the dealer = 22800 + 1200 = ₹24000

Selling price of the article = ₹30000

Profit percentage = $$\ \frac{30000-24000}{24000}\times100=\frac{6000}{24000}\times100=25\%$$

Hence, the correct answer is Option D


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App