Instructions

In these questions, two equations numbered I and II are given. You have to solve both the equations and select the appropriate option.

Question 51

I. $$x^{2}=16$$
II. $$2y^{2}-17y+36=0$$

Solution

$$x^2 = 16$$
$$x = 4, -4$$

$$2y^2-17y+36 = 0$$
$$(2y-9)(y-4) = 0$$
$$y = \frac{9}{2}, 4$$

$$x \leq y$$

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I. $$x^{2}=16$$II. $$2y^{2}-17y+36=0$$