Question 46

The greatest number,that divides 43, 91 and 183 so as to leave the same remainder in each case, is

Solution

3 numbers are 43,91,183

largest number is 183

smallest number is 43

subtract smallest number from both the highest number

so 183 - 43 = 140

91 - 43 = 48

91 is smaller than 183, so subtract 91 from 183

183 - 91 = 92

now we have 3 numbers 140,48,92

so HCF of 140,48,92 = 4

thus the greatest number,that divides 43, 91 and 183 so as to leave the same remainder in each case, is 4

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