Question 46
The greatest number,that divides 43, 91 and 183 so as to leave the same remainder in each case, is
Solution
3 numbers are 43,91,183
largest number is 183
smallest number is 43
subtract smallest number from both the highest number
so 183 - 43 = 140
91 - 43 = 48
91 is smaller than 183, so subtract 91 from 183
183 - 91 = 92
now we have 3 numbers 140,48,92
so HCF of 140,48,92 = 4
thus the greatest number,that divides 43, 91 and 183 so as to leave the same remainder in each case, is 4
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