Question 46

$$tan^2Asin^2A$$ is equal to

Solution

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Expression : $$tan^2Asin^2A$$

Using, $$(sin^2A+cos^2A=1)$$

= $$\frac{sin^2A}{cos^2A} (1-cos^2A)$$

= $$\frac{sin^2A}{cos^2A}-sin^2A$$

= $$tan^2A-sin^2A$$

=> Ans - (A)

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