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What is the value of the expression $$a^{3}-5+\frac{128}{16a}$$, when $$a=2$$ ?
Given, $$a = 2$$
$$\therefore\ a^3-5+\frac{\ 128}{16a}=\left(2\right)^3-5+\frac{\ 128}{16\left(2\right)}=8-5+4=7$$
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