Question 4

What is the value of the expression $$a^{3}-5+\frac{128}{16a}$$, when $$a=2$$ ?

Solution

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Given, $$a = 2$$

$$\therefore\ a^3-5+\frac{\ 128}{16a}=\left(2\right)^3-5+\frac{\ 128}{16\left(2\right)}=8-5+4=7$$

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