Two whole numbers are such that the square of first number exceeds the second by 112 and the ratio of the numbers is 4:3. What is the value of smaller number?
Let the numbers be $$4x$$ and $$3x$$
According to ques,
=> $$(4x)^2-(3x)^2=112$$
=> $$16x^2-9x^2=7x^2=112$$
=> $$x^2=\frac{112}{7}=16$$
=> $$x=\sqrt{16}=4$$
$$\therefore$$ Smaller number = $$3\times4=12$$
=> Ans - (C)
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