Shaan got a total of Rs. 912 in the denomination of equal numbers of Rs. 1, Rs. 5 and Rs. 10 coins. How many coins do Shaan posses?
Let there are $$x$$ type of each coin.
Total amount = $$(x\times1)+(x\times5)+(x\times10)=912$$
=> $$x+5x+10x=912$$
=> $$x=\frac{912}{16}=57$$
$$\therefore$$ Total number of coins of each denomination = $$57\times3=171$$
=> Ans - (C)
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