Question 4

Determine the value of 'x' when $$\sqrt[3]{3^x}=27$$

Solution

Expression : $$\sqrt[3]{3^x}=27$$

=> $$(3)^{\frac{x}{3}}=(3)^3$$

Comparing both exponents, we get :

=> $$\frac{x}{3}=3$$

=> $$x=3\times3=9$$

=> Ans - (C)

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