Two whole numbers are such that the cube of first number exceeds the cube of second by 61 and the ratio of the numbers is 5:4. What is the value of larger number?
Let the numbers be $$5x$$ and $$4x$$
According to ques,
=> $$(5x)^3-(4x)^3=61$$
=> $$125x^3-64x^3=61x^3=61$$
=> $$x^3=\frac{61}{61}=1$$
=> $$x=\sqrt[3]{1}=1$$
$$\therefore$$ Larger number = $$5\times1=5$$
=> Ans - (C)
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