Question 39
The side QR of ΔPQR is produced to S. If ∠PRS = 105° and ∠Q = (1/2)∠P, then what is the value of ∠P?
Solution
Let $$\angle Q=x$$, => $$\angle P=2x$$
Using exterior angle property in $$\triangle$$ PQR,
=> $$\angle$$ P + $$\angle$$ Q = $$\angle$$ PRS
=> $$2x+x=105^\circ$$
=> $$x=\frac{105^\circ}{3}=35^\circ$$
$$\therefore$$ $$\angle P=2\times35^\circ=70^\circ$$
=> Ans - (C)
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