If sec 15θ = cosec 15θ (0° < θ < 10°) then value of θ is
Given : $$sec(15\theta)=cosec(15\theta)$$
=> $$\frac{1}{cos(15\theta)}=\frac{1}{sin(15\theta)}$$
=> $$\frac{sin(15\theta)}{cos(15\theta)}=1$$
=> $$tan(15\theta)=1$$
=> $$15\theta=tan^{-1}(1)$$
=> $$15\theta=45^\circ$$
=> $$\theta=\frac{45}{15}=3^\circ$$
=> Ans - (D)
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