Question 38

If $$x=(0.25)^{\frac{1}{2}}, y=(0.4)^2,z=(0.126)^{\frac{1}{3}}$$ then

Solution

Given : $$x=(0.25)^{\frac{1}{2}}$$

=> $$x=0.5$$ ---------(i)

$$y=(0.4)^2$$

=> $$y=0.16$$ ------(ii)

$$z=(0.126)^{\frac{1}{3}}$$

$$\because$$ $$(0.125)^{\frac{1}{3}}=0.5$$

=> $$z$$ > $$0.5$$ ----------(iii)

$$\therefore$$ Combining equations (i),(ii) and (iii), we get : $$z>x>y$$

=> Ans - (C)

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