If $$x=(0.25)^{\frac{1}{2}}, y=(0.4)^2,z=(0.126)^{\frac{1}{3}}$$ then
Given : $$x=(0.25)^{\frac{1}{2}}$$Â
=> $$x=0.5$$ ---------(i)
$$y=(0.4)^2$$
=> $$y=0.16$$ ------(ii)
$$z=(0.126)^{\frac{1}{3}}$$
$$\because$$ $$(0.125)^{\frac{1}{3}}=0.5$$
=> $$z$$ > $$0.5$$ ----------(iii)
$$\therefore$$ Combining equations (i),(ii) and (iii), we get : $$z>x>y$$
=> Ans - (C)
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