Question 36

If 7x - [3(2x - 3)]/2 = 1/2, then what is the value of x?

Solution

Expression : $$7x-[\frac{3}{2}(2x-3)]=\frac{1}{2}$$

= $$7x-(\frac{6x-9}{2})=0.5$$

= $$\frac{14x-6x+9}{2}=0.5$$

= $$8x+9=0.5\times2=1$$

= $$8x=1-9=-8$$

= $$x=\frac{-8}{8}=-1$$

=> Ans - (A)

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