Solution
Expression : $$7x-[\frac{3}{2}(2x-3)]=\frac{1}{2}$$
= $$7x-(\frac{6x-9}{2})=0.5$$
= $$\frac{14x-6x+9}{2}=0.5$$
= $$8x+9=0.5\times2=1$$
= $$8x=1-9=-8$$
= $$x=\frac{-8}{8}=-1$$
=> Ans - (A)
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