Question 35

$$PQRS$$ is a square whose side is $$20 cm$$. By joining opposite vertices of $$PQRS$$ are get four triangles. What is the sum of the perimeters of the four triangles?

Solution

Side of square is 20 cm.

So, diagonal of square is 20√2 cm.

So,to calculate perimeter of triangle,we get to count each diagonal 2 times and 4 sides only one time .

So, required perimeter=4×20+4×20√2

=(80+80√2) cm.

B is correct choice.

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