Which two numbers should be interchanged to make the given equation correct?
$$9 + 6 \div 4 − 5 + 3 = 10$$

$$9+\frac{6}{4}-5+3=10$$

A. 6 and 10
$$9+\frac{10}{4}-5+3=6$$

$$9+2.5-5+3=6$$

$$11.5-5+3=6$$

$$6.5+3=6$$

$$9.5=6$$

B. 10 and 5

$$9+\frac{6}{4}-5+3=10$$

$$9+\frac{6}{4}-10+3=5$$

$$9+1.5-10+3=5$$

$$10.5-10+3=5$$

$$10.5-13=5$$

$$-2.5=5$$

C. 9 and 3

$$9+\frac{6}{4}-5+3=10$$

$$3+\frac{6}{4}-5+9=10$$

$$\frac{9}{4}-5+9=10$$

$$2.25-5+9=10$$

$$-2.75+9=10$$

$$6.25=10$$

D. 4 and 3
$$9+\frac{6}{4}-5+3=10$$

$$9+\frac{6}{3}-5+4=10$$

$$9+2-5+4=10$$

$$11-5+4=10$$

$$6+4=10$$

$$10=10$$

Hence Option D is the correct answer