Question 33

Which two numbers (NOT digits) and two signs need to be interchanged to make the given equation correct?
$$35 \div 4 \times 48 + 70 - 10 = 40$$

Solution

$$\frac{35}{4}\times\ 48+70-10=40$$

A.35 and 48 - and /
$$\frac{48}{4}\times\ 35+70-10=40$$

$$12\times\ 35+70-10=40$$

$$420+60=40$$

$$480=40$$

B.70 and 10 + and -

$$\frac{35}{4}\times\ 48+70-10=40$$

$$\frac{35}{4}\times\ 48-10+70=40$$

$$\frac{35}{4}\times\ 38+70=40$$

$$8.75\times\ 38+70=40$$

$$332.5+70=40$$

$$402.5=40$$

C.4 and 48 * and +

$$\frac{35}{48}+4\times\ 70-10=40$$

$$0.729+4\times\ 70-10=40$$

$$0.729+4\times\ 60=40$$

$$0.729+240=40$$

$$240.72=40$$

D.70 and 48 / and *
$$\frac{35}{4}\times\ 48\ +\ 70-10=40$$

$$35\times\ \frac{4}{70}+48-10=40$$

$$\frac{140}{70}+48-10=40$$

$$2+38=40$$

$$40=40$$

Hence option D is the correct answer


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