Question 33
Triangle $$PQR$$ is inscribed in the circle whose radius is 14 cm. If $$PQ$$ is the diameter of the circle and $$PR = 10$$ cm, then what is the area of the triangle $$PQR$$?
Solution
As PQ is diameter ,then triangle PQR is right angle triangle.
So,$$QR=√(28^2-10^2)=√684=6√19$$.
So, area of PQR=(1/2)×PR×QR
=(1/2)×10×6√19=30√19.
B is correct choice.
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