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Question 33
In the following question, select the missing number from the given series.
56, 65, 81, 106, ?, 191
Solution
Squares of consecutive integers are added.
56 $$+(3)^2$$ = 65
65Â $$+(4)^2$$ =Â 81
81Â $$+(5)^2$$ =Â 106
106Â $$+(6)^2$$ =Â 142
142Â $$+(7)^2$$ =Â 191
=> Ans - (A)
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