Question 33
In the following question, select the missing number from the given series.
56, 65, 81, 106, ?, 191
Solution
Squares of consecutive integers are added.
56 $$+(3)^2$$ = 65
65 $$+(4)^2$$ = 81
81 $$+(5)^2$$ = 106
106 $$+(6)^2$$ = 142
142 $$+(7)^2$$ = 191
=> Ans - (A)
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