Question 33

In the following question, select the missing number from the given series.
56, 65, 81, 106, ?, 191

Solution

Squares of consecutive integers are added.

56 $$+(3)^2$$ = 65

65 $$+(4)^2$$ = 81

81 $$+(5)^2$$ = 106

106 $$+(6)^2$$ = 142

142 $$+(7)^2$$ = 191

=> Ans - (A)


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