In these questions, two equations numbered I and II are given. You have to solve both the equations and select the appropriate option.
$$2x^2-9x+10 = 0$$
$$(2x-5)(x-2) = 0$$
$$x = 2, \frac{5}{2}$$
$$2y^2-13y+20 = 0$$
$$(2y-5)(y-4) = 0$$
$$y = \frac{5}{2}, 4$$
$$x\leq y$$
Create a FREE account and get: