Instructions

In these questions, two equations numbered I and II are given. You have to solve both the equations and select the appropriate option.

Question 32

I. $$x^{2}=144$$
II. $$y^{2}-24y+144=0$$

Solution

$$x^2 = 144$$
$$x = -12, 12$$

$$y^-24y+144 = 0$$
$${(y-12)}^2 = 0$$
$$y =12$$

$$x\leq y$$

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I. $$x^{2}=144$$II. $$y^{2}-24y+144=0$$