Instructions
In these questions, two equations numbered I and II are given. You have to solve both the equations and select the appropriate option.
Solution
$$2x^2+15x+27 = 0$$
$$(2x+9)(x+3) = 0$$
$$x = -\frac{9}{2}, -3$$
$$2y^2+7y+6 = 0$$
$$(2y+3)(y+2) = 0$$
$$y = -\frac{3}{2}, -2$$
$$x < y$$
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