Instructions

In these questions, two equations numbered I and II are given. You have to solve both the equations and select the appropriate option.

Question 35

I. $$3x^{2}-13x+12=0$$
II.$$3y^{2}-13y+14=0$$

Solution

$$3x^2-13x+12 = 0$$
$$(3x-4)(x-3) = 0$$
$$x = \frac{4}{3}, 3$$

$$3y^2-13y+14 = 0$$
$$(3y-7)(y-2) = 0$$
$$y = 2, \frac{7}{3}$$

relationship between x and y cannot be established

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I. $$3x^{2}-13x+12=0$$II.$$3y^{2}-13y+14=0$$