Question 31

If $$\frac{2p}{p^2-2p+1}=\frac{1}{4}$$, then the value of $$p+\frac{1}{p}$$ will be

Solution

Given : $$\frac{2p}{p^2-2p+1}=\frac{1}{4}$$

=> $$8p=p^2-2p+1$$

=> $$p^2+1=8p+2p$$

=> $$p^2+1=10p$$

=> $$\frac{p^2+1}{p}=10$$

=> $$p+\frac{1}{p}=10$$

=> Ans - (B)


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