If $$\frac{2p}{p^2-2p+1}=\frac{1}{4}$$, then the value of $$p+\frac{1}{p}$$ will be
Given :Â $$\frac{2p}{p^2-2p+1}=\frac{1}{4}$$
=> $$8p=p^2-2p+1$$
=> $$p^2+1=8p+2p$$
=> $$p^2+1=10p$$
=> $$\frac{p^2+1}{p}=10$$
=> $$p+\frac{1}{p}=10$$
=> Ans - (B)
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